python使用json将字符串转字典报错的解决

问题描述

C:\Users\lenovo\AppData\Local\Programs\Python\Python37\python.exe D:/360MoveData/Users/lenovo/Desktop/startProject/OAS.Cloud.PAAS_Interface/TestCases/UM/Test_01_register.py
D:\360MoveData\Users\lenovo\Desktop\startProject\OAS.Cloud.PAAS_Interface\common\CaseData.ini
Traceback (most recent call last):
  File "D:/360MoveData/Users/lenovo/Desktop/startProject/OAS.Cloud.PAAS_Interface/TestCases/UM/Test_01_register.py", line 73, in <module>
    Test_UM_register().test_01()
  File "D:/360MoveData/Users/lenovo/Desktop/startProject/OAS.Cloud.PAAS_Interface/TestCases/UM/Test_01_register.py", line 52, in test_01
    headers = json.loads(dataList[1])
  File "C:\Users\lenovo\AppData\Local\Programs\Python\Python37\lib\json\__init__.py", line 348, in loads
    return _default_decoder.decode(s)
  File "C:\Users\lenovo\AppData\Local\Programs\Python\Python37\lib\json\decoder.py", line 337, in decode
    obj, end = self.raw_decode(s, idx=_w(s, 0).end())
  File "C:\Users\lenovo\AppData\Local\Programs\Python\Python37\lib\json\decoder.py", line 353, in raw_decode
    obj, end = self.scan_once(s, idx)
json.decoder.JSONDecodeError: Expecting property name enclosed in double quotes: line 1 column 2 (char 1)

Process finished with exit code 1

如上,json.decoder.JSONDecodeError: Expecting property name enclosed in double quotes

意思为jsondecodeerror:期望属性名用双引号括起来

问题分析

我查看我的原始数据,格式为:

{‘Content-Type': ‘application/json'}

python对单引号、双引号都认为是引号,但对于json来说,它识别是按照双引号来的。因此,凡是用json来格式转换,必定将单引号转为双引号,必要的时候加“\”转义。

通过上述问题分析,我们得到两个解决方案:

  • 将原格式换成双引号;
  • 换其它方式来转换

问题解决

1、将原格式换成双引号

{‘Content-Type': ‘application/json'}

改为

{“Content-Type”: “application/json”}

验证结果:

成功

2、换其它方式来转换

headers = eval(dataList[1])
 # headers = json.loads(dataList[1])

验证结果:

成功

总结

作者:Lion King原文地址:https://blog.csdn.net/weixin_43431593/article/details/104080773

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